A SIMPLE MATH PROBLEM...

Hi everyone...Do you like math problems?here is a simple problem ; what is the answer?A quart bottle contains a mixture that is 1/3 antifreeze, 2/3 water. A half gallon bottle contains a mixture that is 3/4 antifreeze, 1/4 water. The contents of the two bottles are poured into a gallon jug. What is the ratio (one integer to another, in the form a:b) of antifreeze to water in the jug?http://www.geom.uiuc.edu/~lori/mathed/problems/league960103.htmlhave fun:)

You need to be a member of MyEnglishClub to add comments!

Join MyEnglishClub

Email me when people reply –

Replies

  • Hi Pham Trang...
    absolutely correct...
    thanks for the nicely explained reply ...
    have a wonderful time:)

    Pham Trang said:
    The ratio of antifreeze (a) to water (b) is 11/7.
    Explaining: In the first bottle, antifreeze makes up 0.25/3 gallon and water makes up 0.5/3 gallon. In second bottle (half gallon bottle) antifreeze makes up 1.5/4 gallon and water makes up 0.5/4 gallon. After pouring all into a gallon jug, antifreeze makes up 0.25/3 + 1.5/4 = 5.5/12 gallon and water makes up 3.5/12 gallon. So the ratio of antifreeze to water is 5.5/12/3.5/12 = 5.5/3.5 = 11/7.
    Nice weekend!
  • The ratio of antifreeze (a) to water (b) is 11/7.
    Explaining: In the first bottle, antifreeze makes up 0.25/3 gallon and water makes up 0.5/3 gallon. In second bottle (half gallon bottle) antifreeze makes up 1.5/4 gallon and water makes up 0.5/4 gallon. After pouring all into a gallon jug, antifreeze makes up 0.25/3 + 1.5/4 = 5.5/12 gallon and water makes up 3.5/12 gallon. So the ratio of antifreeze to water is 5.5/12/3.5/12 = 5.5/3.5 = 11/7.
    Nice weekend!
This reply was deleted.