If we have:
f(x)= Ln(x^9)
g(x)= x^(2/3)
h(x)= e^(x)
Then, what is f(g(h(x)))?
1- 6x
2- 9x
3- 10x
4- e^(9x)
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If we have:
f(x)= Ln(x^9)
g(x)= x^(2/3)
h(x)= e^(x)
Then, what is f(g(h(x)))?
1- 6x
2- 9x
3- 10x
4- e^(9x)
You need to be a member of MyEnglishClub to add comments!
Replies
Please let me write its solution here:
f(x)= Ln(x^9) =9 lnx
g(x)=x^(2/3)
h(x)=e^x
f(g(h(x))) = f(g(e^x)) = f{(e^x)^2/3} = 9 ln {(e^x)^2/3}={(2/3)*9} ln (e^x)= 6ln (e^x)= 6x
Very good!
Well done, dear Sue!
Yes, that is right.
Please, tell us about its solution that we learn your way, too.